[next] [prev] [up] Date: Tue, 14 May 91 18:14:11 -0700 (PDT)
[next] [prev] [up] From: Ronnie Kon <kon@bach.stanford.edu >
~~~ [prev] [up] Subject: Re: 5by cubes

I suspect this is why there are (and will probably never be) cubes of
orders greater than 5. I believe (though have not proved) that the 5 cube
contains all the complexity that is possible. Adding more cubies would only
increase the amount of time needed to solve.

On the other hand, a 5X (or any cube of odd order) will still have the
constraints imposed by a fixed center. As a single example, the 4X here in
my office is completely "solved" except that two opposite corners are
swapped. That's not something that can happen on a cube of odd order (at
least I don't think so, but I would love to be proved wrong ;).

Wow! I could have sworn I have gotten to this position before, but you are
very definitely correct. The state with two diagonal corners swapped is in
the orbit with edge cubies exchanged.


[next] [prev] [up] [top] [help]