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With Jerry's help I have found a process for one of the <U, R>

antipodes! Note the number of turns required in the h turn metric.

I applied the turn R1 to the position so the program only needed to

search 24 q turns deep.

First Antipodal Process (25 q, 20 q) UR13 = U2 R1 U3 R2 U3 R2 U3 R1 U2 R3 U1 R3 U3 R1 U1 R2 U1 R3 U1 R3 Also.... UR13 ^ 2 = I

Using current techniques, this required a run of about 11 hours.

It remains to be seen how the Kociemba algorithm resolves this

position, and I will try this next.

Although somewhat unrelated, I found a square's group process

for 6 X order 2 (the pons asinorum) by hand, which does

not move the centres:

U2 B2 L2 U2 D2 L2 F2 T2 F2 U2 L2 F2 B2 L2 D2 F2 (16 h, 32 q)-> Mark <-

email: mark.longridge@canrem.com