[next] [prev] [up] Date: Wed, 07 Dec 94 20:43:00 -0700 (PST)
[next] [prev] [up] From: Martin Schoenert <Martin.Schoenert@math.rwth-aachen.de >
[next] ~~~ [up] Subject: Corrections
Dan Hoey writes in his e-mail message of 1994/11/08

Martin.Schoenert@math.rwth-aachen.de writes:

The way I view this is as follows. The entire cube group C is a
permutation group group on 6*9 points, generated by the six face
turns U, D, L, R, F, B; the three middle slice turns M_U, M_L,
M_F; and the reflection S. This group has a subgroup M of
symmetries of the cube (of order 48), generated by U M_U D',
L M_L R', F M_F B', and S. Another subgroup is G, generated by
the six face turns, which has index 48 in G. G is a normal
divisor of C, G is the semidirect product of M and G. The same is
true for GE and GC.

I think two of those G's are supposed to be C's, right?

Correct (wouldn't make any sense for a group G to be a subgroup in itself
of index 48 ;-).

Dan Hoey continues

As for when I wrote

M class             Edge         Corner       Corner times edge
  (class size)      F.P.          F.P.             / (96*class size)

That's not a typo. I was just saying that column 4 is equal to column
2 times column 3, divided by column 1, divided by 96. Perhaps I
should have factored column 1 out of columns 2 and 3 first to avoid
this confusion.

Again you are correct. But it was confusing, at least to me.

Have a nice day.


-- .- .-. - .. -.  .-.. --- ...- . ...  .- -. -. .. -.- .-
Martin Sch"onert,   Martin.Schoenert@Math.RWTH-Aachen.DE,   +49 241 804551
Lehrstuhl D f"ur Mathematik, Templergraben 64, RWTH, 52056 Aachen, Germany

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